PhysicsA cubical block of wood 10 cm on a side floats at the interface between oil and water with its lower surface horizontal and 4cm below the interface .The density of oil is 0.6 g cm−3.The mass of block is           

A cubical block of wood 10 cm on a side floats at the interface between oil and water with its lower surface horizontal and 4cm below the interface .The density of oil is 0.6gcm3.The mass of block is

           

  1. A

    706 g

  2. B

    607 g

  3. C

    760 g

  4. D

    670 g

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    Solution:

    Weight of block = Weight of displaced oil + Weight of displaced water
    mg=V1ρ0g+V2ρWg m=(10×10×6)×0.6+(10×10×4)×1=760gm

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