PhysicsA disc rotates freely with rotational kinetic energy E about a normal axis through centre. A ring having the same radius but double the mass of disc is now, gently placed on the disc. The new rotational kinetic energy of the system would be

A disc rotates freely with rotational kinetic energy E about a normal axis through centre. A ring having the same radius but double the mass of disc is now, gently placed on the disc. The new rotational kinetic energy of the system would be

  1. A

    E/2

  2. B

    2E/5

  3. C

    E/5

  4. D

    E/3

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    Solution:

    From Law of conservation of angular momentum :
    MR22ω=MR22+(2M)R2ω2

    ω2=MR22ω5MR22=ω5

    The ratio of energies in both the cases is E1E2=12212(5I)ω52=5

    E2=E5

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