PhysicsA metal rod has a length of 1m at 30°C. ‘α’ of metal is 2.5 × 10–5/°C. The temperature at which it will be shortened by 1mm is

A metal rod has a length of 1m at 30°C. 'α' of metal is 2.5 × 10–5/°C. The temperature at which it will be shortened by 1mm is

  1. A

    –30°C

  2. B

    –40°C

  3. C

    –10°C

  4. D

    10°C

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    Solution:

    l = 1m, t1 = 30oC, t2 = ?
    α=2.5 x 10-5/ oC, l=-1mm=-1 x 10-3m
    we have α=llt2.5 x 10-5=-1 x 10-3(10)(t2-30)
    t2 = -10oC

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