A particle executes SHM with a frequency f, The frequency with which its KE oscillates is:

A
f/2
B
f
C
2f
D
4f

Solution:

$y = A \sin ω t$

$\frac{d y}{d t} = A ω \cos ω t$

$K E = \frac{1}{2} m v^{2}$

$= \frac{m A^{2} ω^{2} \cos^{2} ω t}{2}$

$= \frac{m A^{2} ω^{2} (1 + \cos 2 ω t)}{4}$

$= \frac{m A^{2} ω^{2}}{4} + \frac{m A^{2} ω^{2} \cos 2 ω t}{4}$

During one complete oscillation, the kinetic energy of the particle executing SHM will be twice. KE will oscillate with frequency double the frequency of SHM, Which is 2f

Solution:

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