A particle executes simple harmonic motion between x = – A and x= +A. The time taken for it to go from 0 to A2 is T1 and to go from A2 to A is T2. Then:

A particle executes simple harmonic motion between x = – A and x= +A. The time taken for it to go from 0 to A2 is T1 and to go from A2 to A is T2. Then:

  1. A

    T1<T2

  2. B

    T1>T2

  3. C

    T1=T2

  4. D

    T1=2T2

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    Solution:

    In simple harmonic motion, the speed of the particle is the maximum at the mean position x = 0, decreases as it moves towards the extreme position becoming zero at the extreme position x = A. Hence the  particle will take shorter time to move from x = 0 to x = A2 than to move from x = A2 to x = A.

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