A particle is subjected to two SHMs, X1=A1 sin ωt and X2=A2 sin ωt+π4. The resultant SHM will have an amplitude of:

A particle is subjected to two SHMs, X1=A1 sin ωt and X2=A2 sin ωt+π4. The resultant SHM will have an amplitude of:

  1. A

    A1+A22

  2. B

    A12+A22

  3. C

    A12+A22+2A1A2

  4. D

    A12+A222

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    Solution:

    Resultant amplitude, 
    AA12+A22+2A1A2cos ϕ
    Here        ϕ=π4
         A=A12+A22+2A1A2
     

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