A particle is subjected to two simple harmonic motions given by, y1=10 sin ωt, y2= 5 sin ωt+π. The maximum speed of the particle is:

A particle is subjected to two simple harmonic motions given by, $y_{1} = 10 \sin ωt, y_{2} = 5 \sin (ωt + π)$ . The maximum speed of the particle is:

A
$\sqrt{10^{2} + 5^{2}} ω$
B
$\sqrt{10^{2} - 5^{2}} ω$
C
$5 ω$
D
$15 ω$

Solution:

$y = y_{1} + y_{2} = 10 \sin ωt + 5 \sin (ωt + π) = 10 \sin ωt - 5 \sin ωt Velocity = \frac{dy}{dt} = 5 ω \cos ωt \Rightarrow maximum speed = 5 ω$

Related content

Extra Questions for Class 9 Maths with Solutions Chapter Wise

FAQ Metallurgy JEE

Conservation of Biodiversity – Definition, Methods, Examples and Strategies

JEE Main Previous Year Papers Questions With Solutions Chemistry Nitro,Amine and Azo Compounds

Democratic Rights Class 9 Extra Questions Civics Chapter 6

Essay on All that Glitters is not Gold in English for Children and Students

Evans Tries an O-level Important Questions Class 12 English

Short and Long Essay on Corruption in English for Children and Students

Holi Wishes SMS and Messages for Mobile and Whatsapp