PhysicsA ping-pong ball of mass m is floating in air by a jet of water emerging out of a nozzle. If the water strikes the ping-pong ball with a speed v and just after collision water falls dead, the rate of mass flow of water in the nozzle is equal to: 

A ping-pong ball of mass m is floating in air by a jet of water emerging out of a nozzle. If the water strikes the ping-pong ball with a speed v and just after collision water falls dead, the rate of mass flow of water in the nozzle is equal to: 

  1. A

    2mgv

  2. B

    mvg

  3. C

    mgv

  4. D

    None of these

    Fill Out the Form for Expert Academic Guidance!l



    +91



    Live ClassesBooksTest SeriesSelf Learning



    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    The impact force F = (dp/dt) where dp = change of momentum of water of mass dm striking  the ball a speed v during time dt. 

    Since water falls dead after collision with the ping-pong ball
    Δp=ΔmvF=vΔmΔtupward on the ball 

    Where ΔmΔt= rate of flow of water in the nozzle. 

    Since the ball is in equilibrium
    Fmg=0F=mg⇒=mgΔmΔt=mgv

    Chat on WhatsApp Call Infinity Learn

      Talk to our academic expert!



      +91


      Live ClassesBooksTest SeriesSelf Learning




      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.