A projectile is moving at 20 m/s at its highest point, where it breaks into two equal parts due to an internal explosion. One part moves vertically up at 30 m/s with respect to the ground. Then the other part will move at:

A projectile is moving at 20 m/s at its highest point, where it breaks into two equal parts due to an internal explosion. One part moves vertically up at 30 m/s with respect to the ground. Then the other part will move at:

  1. A

    20 m/s

  2. B

    1013m/s

  3. C

    50 m/s

  4. D

    30 m/s

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    Solution:

    Using linear momentum conservation,

    2m×20i^=m×30j^ + m×v v = 40i^ - 30j^
    Therefore, 

    v=302+402=50 m/s

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