A small steel ball falls through a syrup at a constant speed of 10 cms–1 . If the steel ball is pulled upwards with a force equal to twice its effective weight, find the terminal velocity of the ball (in cm/s) in this case.

A small steel ball falls through a syrup at a constant speed of . If the steel ball is pulled upwards with a force equal to twice its effective weight, find the terminal velocity of the ball (in cm/s) in this case.

Fill Out the Form for Expert Academic Guidance!l

+91

Live ClassesBooksTest SeriesSelf Learning

Verify OTP Code (required)

Solution:

case(i):

$\mathrm{B}+6\pi \eta \mathrm{rv}=\mathrm{mg}-----\left(i\right)$

Case (ii) :

$\mathrm{F}+\mathrm{B}=\mathrm{mg}+6\pi \eta r{v}_{\mathrm{t}}$

$2\mathrm{mg}-2\mathrm{B}+\mathrm{B}=\mathrm{mg}+6\pi \eta r{v}_{\mathrm{t}}$

$\mathrm{mg}-\mathrm{B}=6\pi \eta {\mathrm{rv}}_{\mathrm{t}}.........\left(ii\right)$

From eqn (i) & (ii)

${\mathrm{v}}_{\mathrm{t}}=\mathrm{v}=10\mathrm{cm}/\mathrm{s}$

Related content

 Important Topic of Physics: Reynolds Number Distance Speed Time Formula Refractive Index Formula Mass Formula Electric Current Formula Electric Power Formula Resistivity Formula Weight Formula Linear Momentum Formula Non Contact Force

+91

Live ClassesBooksTest SeriesSelf Learning

Verify OTP Code (required)