PhysicsA steel wire of length 20 cm is stretched to increase its length by 0.2 cm. Find the lateral strain in the wire if the Poisson’s ratio for steel is 0.19.

A steel wire of length 20 cm is stretched to increase its length by 0.2 cm. Find the lateral strain in the wire if the Poisson’s ratio for steel is 0.19.

A
0.0019
B
0.0008
C
0.019
D
0.008

Solution:

l = 20cm $∆$ l = 0.2cm
$σ = 0.19 = \frac{∆ b / b}{∆ l / l} \frac{∆ b}{b} = σ \frac{∆ l}{l} = 0.19 x \frac{0.2}{20} = 0.0019$

Related content

Difference Between Mass and Weight

Differences & Comparisons Articles in Physics

Important Topic of Physics: Reynolds Number

Distance Speed Time Formula

Refractive Index Formula

Mass Formula

Electric Current Formula

Electric Power Formula

Resistivity Formula

Weight Formula