A string of length L and force constant k is stretched to obtain extension l. It is further stretched to obtainextension l1. The work done in second stretching is [MHT CET 2014]

A string of length L and force constant k is stretched to obtain extension l. It is further stretched to obtain
extension l1. The work done in second stretching is [MHT CET 2014]

  1. A

    12kl12l+l1

  2. B

    12kl12

  3. C

    12kl2+l12

  4. D

    12kl12-l2)

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    Solution:

    Work done in stretching a string to obtain an extension I,

    W1=12kl2

    Similarly, work done is stretching a string to obtain extension

    l+l1,  W2=12kl1+l2 

    Now, work done in second stretching,

    W2=W2'-W1=12kl1+l2-12kl2=12kl12l+l1

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