A train running on a metre gauge track with a speed of 25ms-1 , the vertical component of the earth’s magnetic field 4×10-5T . The emf generated between the rails is

A train running on a metre gauge track with a speed of $25 m s^{- 1}$ , the vertical component of the earth’s magnetic field $4 \times 10^{- 5} T$ . The emf generated between the rails is

A
$4 \times 10^{- 3} V$
B
$10^{- 3} V$
C
$4 \times 10^{- 4} V$
D
$8 \times 10^{- 4} V$

Solution:

given that $l = 1, B = 4 \times 10^{- 5} T, V = 25 m s^{- 1}$

$l = B l v = 4 \times 10^{- 5} \times (1 m) (25)$

(Consider length between two rails is 1m) = $10^{- 3}$ volt

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