PhysicsA trolley of mass 360 kg is lying on a horizontal frictionless surface. A man of mass 40 kg runs with uniform speed on the trolley by a distance of 2m in 0.5 second. What is the velocity of the trolley relative to earth?

A trolley of mass 360 kg is lying on a horizontal frictionless surface. A man of mass 40 kg runs with uniform speed on the trolley by a distance of 2m in 0.5 second. What is the velocity of the trolley relative to earth?

  1. A

    0.8 m/s 
     

  2. B

    0.4 m/s 
     

  3. C

    1.6m /s

  4. D

    2.2m/s 
     

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    Solution:

    From the question,

    Man+Trolley System:

    Vcom=0

    0=Mvt/e+mvm/e

    vm/t=212=4

    vm/t=vm/e-vt/e

    vm/e=vm/t+vt/e

    Mvt/e+m(vm/t+vt/e)=0

    (M+m)vt/e+mvm/t=0

    vt/e=-mvm/tM+m=-40×4400=-0.4m/s

    Hence the correct answer is 0.4m/s

     

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