PhysicsA wire can be broken by 400 kg.wt. The load required to break the wire of double the thickness of the same material will be –

A wire can be broken by 400 kg.wt. The load required to break the wire of double the thickness of the same material will be -

We know that,

$B r e a k i n g s t r e s s = \frac{F}{A}$

$F \propto r^{2}$ Because breaking stress is same,

$\frac{F_{2}}{F_{1}} = {(\frac{r_{2}}{r_{1}})}^{2} \frac{F_{2}}{400} = {(\frac{2 r}{r})}^{2} F_{2} = 1600 k g w t$

Hence the correct answer is 1600 kg wt.

Related content

Distance Speed Time Formula

Refractive Index Formula

Mass Formula

Electric Current Formula

Electric Power Formula

Resistivity Formula

Weight Formula

Linear Momentum Formula