An ac voltage is applied to a resistance R and inductor L in series. If Rand the inductive reactance are both equal to 3 Ω, the phase difference between the applied voltage and the current in the circuit is :

An ac voltage is applied to a resistance R and inductor L in series. If Rand the inductive reactance are both equal to 3 $\mathrm{\Omega }$, the phase difference between the applied voltage and the current in the circuit is :

1. A

$\frac{\mathrm{\pi }}{6}$

2. B

$\frac{\mathrm{\pi }}{4}$

3. C

$\frac{\mathrm{\pi }}{2}$

4. D

Zero

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Solution:

$\mathrm{\varphi }={\mathrm{tan}}^{-1}\left(\frac{{\mathrm{X}}_{\mathrm{L}}}{\mathrm{R}}\right)={\mathrm{tan}}^{-1}\left(\frac{3}{3}\right)={\mathrm{tan}}^{-1}\left(1\right)=\frac{\mathrm{\pi }}{4}$

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