An ac voltage is applied to a resistance R and inductor L in series. If Rand the inductive reactance are both equal to 3 Ω, the phase difference between the applied voltage and the current in the circuit is :

An ac voltage is applied to a resistance R and inductor L in series. If Rand the inductive reactance are both equal to 3 $Ω$ , the phase difference between the applied voltage and the current in the circuit is :

A
$\frac{π}{6}$
B
$\frac{π}{4}$
C
$\frac{π}{2}$
D
Zero

Solution:

$ϕ = \tan^{- 1} (\frac{X_{L}}{R}) = \tan^{- 1} (\frac{3}{3}) = \tan^{- 1} (1) = \frac{π}{4}$

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