An electric bulb rated for 500 watts at 100 volts is used in a circuit having a 200 volts supply. The resistance R that must be put in series the bulb, so that the bulb delivers 500 watt is …… ohm. 

An electric bulb rated for 500 watts at 100 volts is used in a circuit having a 200 volts supply. The resistance R that must be put in series the bulb, so that the bulb delivers 500 watt is …… ohm. 

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    Solution:

    We know, 

     Power P=V2RRbulb =V2P=100×100500=20Ω

    This would be possible only when R=20Ω is in series with the bulb resistance Rbulb=20Ωbecause in that case both resistances will share equal potential difference of 100 V each. 

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