An electron and a photon have the same de Broglie wavelength. Then the kinetic energy of the electron is

 An electron and a photon have the same de Broglie wavelength. Then the kinetic energy of the electron is

  1. A

    equal to the kinetic energy of the photon

  2. B

     greater than the kinetic energy of the photon

  3. C

    zero

  4. D

     infinity
     

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    Solution:

    λ=hmv=h(2mE)  Thus, meEe=mpEp EeEp=mpme>1 mp>me or Ee>Ep

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