Displacement of a particle executing SHM can be expressed as x=a sin ωt+δAt t = 0, it is observed that the particle is at x=a2 and, moving along positive r-direction. Then δ could be:

Displacement of a particle executing SHM can be expressed as $x = a \sin (ωt + δ)$ At t = 0, it is observed that the particle is at $x = \frac{a}{2}$ and, moving along positive r-direction. Then $δ$ could be:

A
$\frac{π}{3}$
B
$\frac{π}{6}$
C
$\frac{5 π}{6}$
D
$\frac{π}{4}$

Solution:

$At t = 0, \frac{a}{2} = a \sin (0 + δ) \Rightarrow \sin δ = \frac{1}{2} \Rightarrow δ = \frac{π}{6}$

Related content

Appreciation Words

Wave Optics Mind Map

Alternating Current Mind Map for Class 12, JEE & NEET

Paramedical Courses After Class 10

Top Courses After 12th Science with PCM, PCB and PCMB

Subject Change Application in School and College

CBSE Class 10 Result 2024: Is the Release Date Early? Check Expected Schedule

Mizoram NEET Merit List 2023

Government Jobs After 12th Arts Stream

Chhattisgarh NEET UG Merit List 2023