Five equal forces of 10N each are applied at one point and all are lying in a plane. If the angles between any two are equal, the resultant force is

Five equal forces of 10N each are applied at one point and all are lying in a plane. If the angles between any two are equal, the resultant force is

1. A

Zero

2. B

10 N

3. C

20 N

4. D

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Solution:

Given that number of forces = 5

Magnitude is equal.

$\left|\stackrel{\to }{a}\right|=\left|\stackrel{\to }{b}\right|=\left|\stackrel{\to }{c}\right|=\left|\stackrel{\to }{d}\right|=\left|\stackrel{\to }{e}\right|$

and angle between any two is equal

So they form regular pentagon as shown.

We get

$\therefore \overline{a}$+$\overline{b}$+$\overline{c}$+$\overline{d}$+$\overline{e}$=$\overline{0}$

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