For a particle executing SHM the KE is given by K – Ko cos2 at.The maximum value of potential energy is:

For a particle executing SHM the KE is given by K - K_o cos² at.The maximum value of potential energy is:

A
K_o
B
zero
C
K_o/2
D
not obtainable

Solution:

Maximum value of $\cos^{2} ωt = 1$
$K_{\max} = K_{0} \cos^{2} ωt = K_{0} {(PE)}_{\max} = {(K)}_{\max} = K_{0}$

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