If a machine gun fires n bullets per second each with kinetic energy K, then the power of the machine gun is

If a machine gun fires n bullets per second each with kinetic energy K, then the power of the machine gun is

A
${nK}^{2}$
B
$\frac{K}{n}$
C
$n^{2} K$
D
$nK$

Solution:

Power of the machine gun

$= \frac{Total work done}{Time} = \frac{n \cdot \frac{1}{2} {mv}^{2}}{t}$

$= n \cdot \frac{1}{2} \frac{{mv}^{2}}{t} (∵ K = \frac{1}{2} {mv}^{2}, t = 1 s)$

$∴$ The power of the machine gun = nK

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