PhysicsIf force on a rocket having exhaust velocity of 300 m/s is 210 N, then rate of combustion of the fuel is

If force on a rocket having exhaust velocity of $300 m/s$ is 210 N, then rate of combustion of the fuel is

Force $= \frac{d \bar{p}}{dt}$

$= \frac{dm \bar{v}}{dt} = \vec{v} \frac{dm}{dt} \to (1)$

using (1)

$210 = 300 \frac{dm}{dt}$

$\frac{dm}{dt} = 0.7 kg/s$

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