If the magnitudes of vectors A→,B→ and C→ and 12,5 and 13 units respectively and A→+B→=C→, the angle between vectors  A→ and B→ is:

If the magnitudes of vectors A,B and C and 12,5 and 13 units respectively and A+B=C, the angle between vectors  A and B is:

  1. A

    0

  2. B

    π

  3. C

    π/2

  4. D

    π/4

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    Solution:

    A+B=CA+B=C
    Let angle between Aand B be θ then A2 + B2 + 2ABcosθ = π/2
     122 + 52 + 2(12)(5)cosθ = 132
    cosθ = 0θ=π2rad
    OR
    132 =122 + 52 i.e.,C2 = A2 + B2
    So,AB

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