If y=x2sin⁡x , then dydx will be

 If y=x2sinx , then dydx will be

  1. A

    x2cosx+2xsinx

  2. B

    2xsinx

  3. C

    x2cosx

  4. D

    2xcosx

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    Solution:

    y=x2sinxdydx=ddxx2sinx=x2dsinxdx+sinxdx2dx ddx(uv)=udvdx+vdvdx=x2[cosx]+sinx[2x] ddxsinx=cosx,dxndx=nxn1=x2cosx+2xsinx

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