In a gravity free space, a man of mass M standing at a height h above the floor, throws a ball of mass m straight down with a speed u. When the ball reaches the floor, the distance of the man above the floor will be

In a gravity free space, a man of mass M standing at a height h above the floor, throws a ball of 
mass m straight down with a speed u. When the ball reaches the floor, the distance of the man above the floor will be

  1. A

    h1+mM

  2. B

    1+Mmh

  3. C

    h

  4. D

    mMh

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    Solution:

    Centre of mass will remain at height h. 

              hCM=m×0+MHm+M=h

                H=h1+mM

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