PhysicsIn a YDSE experiment, one of the slits is covered with a glass plate of thickness (2.4×10−4) meter, refractive index of which varies with time as μ=t2+12t+8. The separation between the slits is 2×10−3 meter and the distance between the plane of slits and the screen is 2 meters.  Find the velocity (in m/s) of the central maxima at t = 4 s.  (Take refractive index of air = 1).(Round off to nearest integer)

In a YDSE experiment, one of the slits is covered with a glass plate of thickness (2.4×104) meter, refractive index of which varies with time as μ=t2+12t+8. The separation between the slits is 2×103 meter and the distance between the plane of slits and the screen is 2 meters.  Find the velocity (in m/s) of the central maxima at t = 4 s.  (Take refractive index of air = 1).

(Round off to nearest integer)

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    Solution:

    (μ1)t0=d×yD

    y=(μ1)t0Ddvelocity of central maxima, 

    v=dydt=(2t+12)×2.4×104×22×103

    at t = 4 sec

    v=4.8m/s

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