In an experiment of meter bridge, a null point is obtained at the centre of the bridge wire. When a resistance of 10 ohm is connected in one gap, the value of resistance in other gap is

# In an experiment of meter bridge, a null point is obtained at the centre of the bridge wire. When a resistance of 10 ohm is connected in one gap, the value of resistance in other gap is

1. A

$10\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\Omega$

2. B

$5\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\Omega$

3. C

$\frac{1}{5}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}\Omega$

4. D

$500\text{\hspace{0.17em}\hspace{0.17em}}\Omega$

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### Solution:

Meter bridge is balanced, therefore

$\text{\hspace{0.17em}}\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{R}}{\mathrm{S}}\text{\hspace{0.17em}}\mathrm{or}\text{\hspace{0.17em}\hspace{0.17em}}1=\text{\hspace{0.17em}}\frac{10}{\mathrm{S}}\text{\hspace{0.17em}}⇒\text{\hspace{0.17em}}\mathrm{S}=10\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{\Omega }$

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