In photo-electric effect, the slope of straight line graph between stopping potential (V0) and frequency of incident light (v) gives

In photo-electric effect, the slope of straight line graph between stopping potential (V₀) and frequency of incident light (v) gives

A
charge on electron
B
work-function of emitter
C
Planck's constant
D
ratio of Planck's constant to charge on electron

Solution:

$hv = {hv}_{0} + {eV}_{0} or V_{0} = \frac{h}{e} v^{'} - \frac{h}{e} v_{0} Comparing it with y = mx + C, we have m = h le$

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