In the circuit shown here, the readings of the ammeter and voltmeter are (Ammeter and voltmeter are ideal)

Solution:

The given circuit can be redrawn as follows:

Current, $\mathrm{i}=\frac{6}{6+4+1}=\frac{6}{11}\mathrm{A}$

Potential difference between A and B,

$\mathrm{V}=\frac{6}{11}\times 10=\frac{60}{11}\mathrm{V}$