In the given circuit, the resistance R has a value that depends on the current in the circuit. R is when I is zero and the increase in the resistance (in Ω ) is numerically equal to half of the current in ampere. What is the value of I in the circuit?

A
8.33A
B
10A
C
12.5A
D
18.5A

Solution:

$\begin{array}{l} R = 20 + \frac{I}{2}, I = \frac{250}{20 + \frac{I}{2}} \Rightarrow I (20 + \frac{I}{2}) = 250 \Rightarrow I^{2} + 4 I - 500 = 0 \\ \Rightarrow (I - 10) (I + 50) = 0 \\ i . e ., I = 10 A \end{array}$

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In the given circuit, the resistance R has a value that depends on the current in the circuit. R is when I is zero and the increase in the resistance (in $Ω$ ) is numerically equal to half of the current in ampere. What is the value of I in the circuit?

Solution:

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