Resistances in the two gaps of a meter bridge are 10 ohm and 30 ohm, respectively. If the resistances are interchanged the balance point shifts by

A
33.3 cm
B
66.67 cm
C
25 cm
D
50 cm

Solution:

$\begin{array}{l} S = (\frac{100 - l}{l}) . R \\ Initially, 30 = (\frac{100 - l}{l}) \times 10 \Rightarrow l = 25 cm \\ Finally, 10 = (\frac{100 - l}{l}) \times 30 \Rightarrow l = 75 cm \end{array}$

So, shift = 50 cm.

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