Seven resistances are connected as shown in the figure. The equivalent resistance between A and B is

Seven resistances are connected as shown in the figure. The equivalent resistance between A and B is

A
$3 Ω$
B
$4 Ω$
C
$4.5 Ω$
D
$5 Ω$

Solution:

The given circuit can be simplified as follows:

Now it is a balanced Wheatstone bridge.
So,

$\Rightarrow R_{AB} = \frac{8 \times 8}{8 + 8} = \frac{64}{16} = 4 Ω$

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