The angle between (A→×B→) and (B→×A→) is:

The angle between ( $\vec{A} \times \vec{B}$ ) and ( $\vec{B} \times \vec{A}$ ) is:

A
zero
B
$π$
C
$π$ /4
D
$π$ / 4

Solution:

$\vec{B} \times \vec{A}$ = - $\vec{A} \times \vec{B}$
angle between them is $π$ .

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