The displacement-time graph of a particle executing SHM as shown in figure. Which of the following statement{s) is/are false?

A
The acceleration is maximum at t = T.
B
The force is zero at $t = \frac{3 T}{4} .$
C
The potential energy equals the total oscillation energy at $t = \frac{T}{2} .$
D
At T/6 potential energy is equal to the kinetic energy.

Solution:

Acceleration is maximum when displacement is maximum. Force is zero when displacement is zero and potential energy is maximum when displacement is maximum. At T/6 displacement is

$x = A \sin \frac{ω T}{6} = A \sin \frac{π}{3} = \frac{\sqrt{3} A}{2} P o t e n t i a l e n e r g y \frac{1}{2} m ω^{2} \frac{3 A^{2}}{4} k i n e t i c e n e r g y = \frac{1}{2} m ω^{2} A^{2} (1 - \frac{1}{4}) = \frac{1}{2} m ω^{2} A^{2} (\frac{3}{4})$

Solution:

Related content