The figure shows a meter-bridge circuit where X=12 Ω and R=18 Ω. The jockey J is at the null point. If R is made 8 Ω through what distance will the jockey J have to be moved to obtain null point again?

The figure shows a meter-bridge circuit where $X = 12 Ω$ and $R = 18 Ω$ . The jockey J is at the null point. If R is made $8 Ω$ through what distance will the jockey J have to be moved to obtain null point again?

A
10 cm
B
20 cm
C
30 cm
D
40 cm

Solution:

$\frac{AJ}{100 - AJ} = \frac{X}{R} = \frac{12}{18} \Rightarrow AJ = 40 cm$

After changing R:

$\begin{array}{l} \frac{{AJ}^{'}}{100 - {AJ}^{'}} = \frac{12}{8} \Rightarrow {AJ}^{'} = 60 cm \\ Shifting : {AJ}^{'} = 20 cm \end{array}$

Related content

Test your English Vocabulary

CUET Exam Dates 2024 – Application Form, Fees, Eligibility

CBSE Class 12 IP Answer Key 2024,Informatics Practices Paper Solution For SET 1, 2, 3, 4

CUET UG Cut Off 2024, Category, Universities and Colleges Wise Expected Cut Off

Modal Verbs

Helping Verbs

Letter To Your Friend About Your School Trip

Action Verbs

CUET 2024 – List of Colleges and Participating Universities Accepting CUET Exam Score

SRMJEEE Online Test Series – Practice Papers