PhysicsThe M.I. of a thin rod about a normal axis through its centre is I. It is bent at the centre such that, the two parts are perpendicular to each other and perpendicular to the axis. The M.I. of the system about the same axis will be

The M.I. of a thin rod about a normal axis through its centre is I. It is bent at the centre such that, the two parts are perpendicular to each other and perpendicular to the axis. The M.I. of the system about the same axis will be

  1. A

    2I

  2. B

    I

  3. C

    I/2

  4. D

    4I

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    Solution:

    I1=I=MI212

    I2=M2122 x 13+M2122 x 13=M2124 x 13 x 2

    =MI212=I   I2=I

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