The M.I. of a thin rod about a normal axis through its centre is I. It is bent at the centre such that, the two parts are perpendicular to each other and perpendicular to the axis. The M.I. of the system about the same axis will be

# The M.I. of a thin rod about a normal axis through its centre is I. It is bent at the centre such that, the two parts are perpendicular to each other and perpendicular to the axis. The M.I. of the system about the same axis will be

1. A

2I

2. B

I

3. C

I/2

4. D

4I

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### Solution:

${\mathrm{I}}_{1}=\mathrm{I}=\frac{{\mathrm{MI}}^{2}}{12}$

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