PhysicsThe network shown in figure is part of a complete circuit. If a certain instant, the current i is 5 A, and is decreasing at a rate of  103  As−1   , then  (VB−VA)   is (in volt)  

The network shown in figure is part of a complete circuit. If a certain instant, the current i is 5 A, and is decreasing at a rate of  103  As1   , then  (VBVA)   is (in volt)
 


 

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    Solution:

    Moving from A to B
     VBVA=[5×103(103)+15+1×5]=15volt
     

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