The wiring of a house has resistance 6  Ω. A 100 W bulb is glowing. If a geyser of 1000 W is switched on, the change in potential drop across the bulb is nearly (Supply voltage is 220 V)

The wiring of a house has resistance 6  Ω. A 100 W bulb is glowing. If a geyser of 1000 W is switched on, the change in potential drop across the bulb is nearly (Supply voltage is 220 V)

  1. A

    nil

  2. B

    23 V

  3. C

    32 V

  4. D

    12 V

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    Solution:

    RBulb=2202100=48.4  Ω

    (i) When only bulb is ON,  VBulb=220×484490=217.4V

    (ii) When geyser is also switched ON, equivalent resistance of bulb and geyser is R=484×48.4484+48.4=44  Ω

    Voltage across the bulb, VBulb=220×4450=193.6V

    Hence, the potential drop is 217.4193.6=23.8  V

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