Three blocks of masses m1,m2 and m3 are connected by massless strings as shown on a frictionless table. They are pulled with a force T3=40N If m1=10kg,m2=6kg and m3=4kg the tension T2 will be

# Three blocks of masses ${\mathrm{m}}_{1},{\mathrm{m}}_{2}$ and ${\mathrm{m}}_{3}$ are connected by massless strings as shown on a frictionless table. They are pulled with a force ${\mathrm{T}}_{3}=40\mathrm{N}$ If ${\mathrm{m}}_{1}=10\mathrm{kg},{\mathrm{m}}_{2}=6\mathrm{kg}$ and ${m}_{3}=4\mathrm{kg}$ the tension ${\mathrm{T}}_{2}$ will be

1. A

20 N

2. B

40 N

3. C

10 N

4. D

32 N

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### Solution:

$a=\frac{F}{{m}_{1}+{m}_{2}+{m}_{3}}=\frac{40}{20}=2\mathrm{m}/{\mathrm{s}}^{2}$

${\mathrm{T}}_{2}=\left({\mathrm{m}}_{1}+{\mathrm{m}}_{2}\right)\mathrm{a}=\left(16\right)2=32\mathrm{N}$

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