PhysicsThree particle each of 1kg mass are placed at corners of a right angled triangle AOB, ‘O’ being the origin of coordinate system (OA and OB along the x-direction and +ve y-direction). If OA = OB =1m, the position vector of centre of mass (in metres) is

Three particle each of 1kg mass are placed at corners of a right angled triangle AOB, ‘O’ being the origin of coordinate system (OA and OB along the x-direction and +ve y-direction). If OA = OB =1m, the position vector of centre of mass (in metres) is

  1. A

    i^+j^3

  2. B

    i^-j^3

  3. C

    2i^+j^3

  4. D

    i^-j^

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    Solution:

    From the question,

    OA=OB=1m

    m1=m2=m3=1kg

    coordinate of O = (0,0)

    coordinate of A = (1,0)

    coordinate of B = (0,1)

    XCOM=(m1x1+m2x2+m3x3)m1+m2+m3=0+1+03=13

    YCOM=(m1y1+m2y2+m3y3)m1+m2+m3=0+0+13=13

    Hence the correct answer is i^+j^3.

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