To get a resultant displacement of 10 m, two displacement vectors, one of magnitude 6 m and another of 8 m, should be combined :

To get a resultant displacement of 10 m, two displacement vectors, one of magnitude 6 m and another of 8 m, should be combined :

A
parallel
B
antiparallel
C
at an angle 60^o
D
perpendicular to each other

Solution:

$|\vec{A} + \vec{B}| = \sqrt{A^{2} + B^{2} + 2 ABcosθ}$
$\Rightarrow 10 = \sqrt{6^{2} + 8^{2} + 2 (6) (8) cosθ}$

$\Rightarrow cosθ = 0$

$\Rightarrow θ = π / 2$

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