PhysicsTwo blocks of masses 2 kg and 1 kg respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are held at rest at the same horizontal level and then released. The distance transversed by centre of mass in 2 seconds is (g = 10 m/s2) 

Two blocks of masses 2 kg and 1 kg respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are held at rest at the same horizontal level and then released. The distance transversed by centre of mass in 2 seconds is (g = 10 m/s2)
 

  1. A

    1.42 m

  2. B

    2.22 m

  3. C

    3.12 m

  4. D

    3.33 m

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    Solution:

    aCM=m1-m2m1+m22 g=2-12+12(10)=109

    SCM=uCMt+12aCMt2

    =0+12109(2)2=2.22m

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