Two blocks of masses 2 kg and 1 kg respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are held at rest at the same horizontal level and then released. The distance transversed by centre of mass in 2 seconds is (g = 10 m/s2)

# Two blocks of masses 2 kg and 1 kg respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are held at rest at the same horizontal level and then released. The distance transversed by centre of mass in 2 seconds is (g = 10 m/s2)

1. A

1.42 m

2. B

2.22 m

3. C

3.12 m

4. D

3.33 m

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### Solution:

${\mathrm{S}}_{\mathrm{CM}}={\mathrm{u}}_{\mathrm{CM}}\mathrm{t}+\frac{1}{2}{\mathrm{a}}_{\mathrm{CM}}{\mathrm{t}}^{2}$

$=0+\frac{1}{2}\left(\frac{10}{9}\right){\left(2\right)}^{2}=2.22\mathrm{m}$

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