Two bodies M and N of equal masses are suspended from two separate massless springs of spring constants k1 and k2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of M to that on N is

# Two bodies M and N of equal masses are suspended from two separate massless springs of spring constants k1 and k2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of M to that on N is

1. A

$\frac{{\mathrm{k}}_{1}}{{\mathrm{k}}_{2}}$

2. B

$\sqrt{\frac{{\mathrm{k}}_{1}}{{\mathrm{k}}_{2}}}$

3. C

$\frac{{\mathrm{k}}_{2}}{{\mathrm{k}}_{1}}$

4. D

$\sqrt{\frac{{\mathrm{k}}_{2}}{{\mathrm{k}}_{1}}}$

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### Solution:

Given,      ${\mathrm{\omega }}_{1}{\mathrm{A}}_{1}={\mathrm{\omega }}_{2}{\mathrm{A}}_{2}$

$\left(\because \omega =\sqrt{\frac{k}{m}}\right)$

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