Two identical rods each of moment of inertia ‘I’ about a normal axis through centre are arranged in the from of a cross. The M.I. of the system about an axis through centre and perpendicular to the plane of system is

# Two identical rods each of moment of inertia ‘I’ about a normal axis through centre are arranged in the from of a cross. The M.I. of the system about an axis through centre and perpendicular to the plane of system is

1. A

2I

2. B

I

3. C

2.5 I

4. D

6I

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### Solution:

Given, the rods are identical, that implies for the cross made of the rods

${\mathrm{I}}_{\mathrm{x}}={\mathrm{I}}_{\mathrm{y}}$

If the axes x, y, and z are perpendicular to one another

${\mathrm{I}}_{0}=\mathrm{I}+\mathrm{I}=2\mathrm{I}$

Hence the correct answer is 2I.

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