Two identical wires are stretched by the same tension of 101 N and each emits a note of frequency 202 Hz. If the tension in one wire is increased by 1 N, then the beat frequency is:

Two identical wires are stretched by the same tension of 101 N and each emits a note of frequency 202 Hz. If the tension in one wire is increased by 1 N, then the beat frequency is:

  1. A

    2 Hz

  2. B

    12Hz

  3. C

    1 Hz

  4. D

    none of these

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    Solution:

    f  T

       f = 12lTμ  ff = 12TT

    f = 2022×1101= 1

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