PhysicsTwo particles of masses 4 kg and 6 kg are at rest separated by 20 m. If they move towards each other under mutual force of attraction, the position of the point where they meet is

Two particles of masses 4 kg and 6 kg are at rest separated by 20 m. If they move towards each other under mutual force of attraction, the position of the point where they meet is

  1. A

    12m from 4kg body

  2. B

    12m from 6kg body

  3. C

    8m from 4kg body

  4. D

    10m from 4kg body

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    Solution:

    m1 = 4kg, m2 = 6kg, d = 20m 

    Since, they are moving due to mutual force, their centre of mass will not move.

    Therefore they will meet at initial position of their centre of mass.
    distance of C.O.M from m1 is
    x1=m2dm1+m2=6 x 204+6=12m

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