When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l).The elastic potential energy stored in the extended wire is [NEET 2019]

When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l).
The elastic potential energy stored in the extended wire is [NEET 2019]

  1. A

    MgL

  2. B

    12Mgl

  3. C

    12MgL

  4. D

    Mgl

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    Solution:

    In stretching a wire, the work done against internal restoring force is stored as elastic potential energy in
    the wire and is given by

    U=W=12× Force (F)×Elongation (/)

    =12Fl=12×Mg×l=12Mgl

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