PhysicsWhen an empty lift is moving down with an acceleration of g4ms-2, the tension in the cable is 9000N. When the lift is moving up with an acceleration of g4ms-2, the tension in the cable is

When an empty lift is moving down with an acceleration of $\frac{g}{4} {ms}^{- 2}$ , the tension in the cable is 9000N. When the lift is moving up with an acceleration of $\frac{g}{4} {ms}^{- 2}$ , the tension in the cable is

A
16, 000N
B
18, 000N
C
12,000N
D
15,000N

Solution:

$T_{1} = m (g - a) = m (g - \frac{g}{4}) = \frac{3 mg}{4} = 9000 N$

$mg = 12000 N$

$T_{2} = m (g + a) = m (g + \frac{g}{4}) = \frac{5 mg}{4} = \frac{5 \times 12000}{4} = 15000 N$

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