When light of wavelength 300 nm (manometer) falls on a photo electric emitter, photo electrons are liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creating photo-emission. What is the ratio of the work-functions of the two emitter ?

# When light of wavelength 300 nm (manometer) falls on a photo electric emitter, photo electrons are liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creating photo-emission. What is the ratio of the work-functions of the two emitter ?

1. A

1:2

2. B

2 :1

3. C

4 : 1

4. D

1 :4

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### Solution:

if ${\mathrm{\lambda }}_{0}$  be the threshold wavelength, then

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