When light of wavelength 300 nm (manometer) falls on a photo electric emitter, photo electrons are liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creating photo-emission. What is the ratio of the work-functions of the two emitter ?

When light of wavelength 300 nm (manometer) falls on a photo electric emitter, photo electrons are liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creating photo-emission. What is the ratio of the work-functions of the two emitter ?

A
1:2
B
2 :1
C
4 : 1
D
1 :4

Solution:

if $λ_{0}$ be the threshold wavelength, then
$W = hc / λ_{0} \frac{W_{1}}{W_{2}} = \frac{λ_{2}}{λ_{1}} = \frac{2}{1}$

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